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page count using oracle
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amisima View Drop Down
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Points: 17 		Post Options Post Options   Thanks (0) Thanks(0)   Quote amisima Quote  Post ReplyReply Direct Link To This Post Topic: page count using oracle
    Posted: 11 July 2003 at 11:09am
Hi,

I am trying to display 10 results per page and have links to next page. I am getting -1 as a page count. I am using rs.pagecount. I am using Oracle as my database, does the pagecount work with an oracle database?

Thanks,

Amisima
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Gullanian View Drop Down
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Points: 4373 		Post Options Post Options   Thanks (0) Thanks(0)   Quote Gullanian Quote  Post ReplyReply Direct Link To This Post Posted: 11 July 2003 at 12:48pm
Not sure what your trying to do, if your writting your own code dont forget integers when defined are set to 0 as default, you might not be counting the 0 as a page.
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amisima View Drop Down
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Points: 17 		Post Options Post Options   Thanks (0) Thanks(0)   Quote amisima Quote  Post ReplyReply Direct Link To This Post Posted: 11 July 2003 at 12:51pm
this is what I have and I get a -1

if rsa.eof= true then
Page_Count = 1
else
response.write(page_count)
Dim Record_Count
count = 1

Page_Count = rsa.PageCount
record_Count = rsa.RecordCount
response.write(page_Count)
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zaboss View Drop Down
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Points: 454 		Post Options Post Options   Thanks (0) Thanks(0)   Quote zaboss Quote  Post ReplyReply Direct Link To This Post Posted: 13 July 2003 at 7:12am

The problems with other dbs then access and MS SQL is that they can not handle the rs.recordcount or rs.absolutepage, so you have to adjust your code.

So, instead of rsa.recordcount you have to use something like (Select count (*) as numrecords from my db where...)

instead of rs.pagecount you must do something like

mypagescount = Round((left(allrecords,9) / pagesize)) + 1

then

record_Count = rsa("numrecords") and so on.
Cristian Banu
Soft 4 web
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