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Months between two dates
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zaboss View Drop Down
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Joined: 20 August 2002
Location: Romania
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Points: 454 		Post Options Post Options   Thanks (0) Thanks(0)   Quote zaboss Quote  Post ReplyReply Direct Link To This Post Posted: 05 February 2004 at 9:45am
There isn much to it...just grab the values of i and instert them into db. That's all.
Cristian Banu
Soft 4 web
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Maxi View Drop Down
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Joined: 24 October 2002
Location: United Kingdom
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Points: 49 		Post Options Post Options   Thanks (0) Thanks(0)   Quote Maxi Quote  Post ReplyReply Direct Link To This Post Posted: 05 February 2004 at 10:13am

Hi zaboss

Thanks for trying to help;). Being an amateur I am not sure how to just Grab the values of i and insert them into the DB or Field.

As I wrote in my previous mail, I would have liked to see what results the Function turned out first (make sure that it does it correctly), before I started trying to feed that result to a form field or database.

Kind Regards and thanks again 

maxi
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zaboss View Drop Down
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Joined: 20 August 2002
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Points: 454 		Post Options Post Options   Thanks (0) Thanks(0)   Quote zaboss Quote  Post ReplyReply Direct Link To This Post Posted: 05 February 2004 at 10:23am 



StrLast = DateDiff("m", Request.Form("EndDate"), Request.Form("StartDate"))
StrStart =DatePart("m", Request.Form("StartDate")
StrEnd = DatePart("m", Request.Form("EndDate")


For i = StrStart to StrEnd
Response.Write ""& i &""


If i > StrEnd then Exit for
next

Just add the line in red. Not sure about the number of doublequottes, though... Maybe should be only 1 pair... Sorry, don't have the time right know.
Cristian Banu
Soft 4 web
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Maxi View Drop Down
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Joined: 24 October 2002
Location: United Kingdom
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Points: 49 		Post Options Post Options   Thanks (0) Thanks(0)   Quote Maxi Quote  Post ReplyReply Direct Link To This Post Posted: 05 February 2004 at 11:00am

Hi Zaboss,

I tried your code on a test page and added some dates to see what results came out of it.
Either I am doing something seriously wrong or there is a problem with this script? The answer that was returned to me was 7? I do not know where the 7 comes from as the answer should be: 8,9,10?
Here is the code that I had on the test page.

<%
StrLast = DateDiff("m", 15-10-2003, 15-08-2003)
StrStart = DatePart("m", 15-08-2003)
StrEnd = DatePart("m", 15-10-2003)

For i = StrStart to StrEnd
Response.Write ""& i &""
If i > StrEnd then Exit for
Next
%>

Regards

Maxi:)



Edited by Maxi
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zaboss View Drop Down
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Joined: 20 August 2002
Location: Romania
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Points: 454 		Post Options Post Options   Thanks (0) Thanks(0)   Quote zaboss Quote  Post ReplyReply Direct Link To This Post Posted: 05 February 2004 at 11:34am

It seems that there is something wrong with the DatePart function's output... If I changed the date to:



<%
StrLast = DateDiff("m", 15-10-2003, 15-08-2003)
StrStart = DatePart("m", date)
StrEnd = DatePart("m", 10/12/2004)
Response.Write strStart
Response.Write "<br>" & strEnd 
Response.Write "<br>"
i = strStart
For i = StrStart to StrEnd
Response.Write ""& i &"" & "; "
If i > StrEnd then Exit for
Next
%>

This is outputing 2; 3; 4; 5; 6; 7; 8; 9; 10; 11; 12;

Which is then easy to insert into db and then grab back. Notice that I have added a small piece for better diferentiate records. I'm afraid I have to leave you with this as here it is already late and my lady is already mad at me. So, you should check what's wrong with the output of datePart function. After you figure it up, just write an instert into db statement for i.
Cristian Banu
Soft 4 web
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