How to retrieve variable value

Dear All,

I am having problem with retrieving variable value and store it into proper table in the database

I want to pass a variable value called "strDisplayFilename" in filePost.asp and save it into "strLogo_file" in event_Update.asp    
filePost.asp and event_Update.asp do not call each other..

yesterday, I used the following way and it doesn't work

In filePost.asp
session("variable") = strDisplayFilename

in event_Update.asp
strLogo_file = session("variable")
session.abandon

this way doesn't do that work I work.
I want to upload a filename from my local pc and save it into a particular table in the database...
The way above just stores the filename into all tables in the database...
Please tell me the problem with the code above and are there any ways to solve the problem

---------------filePost.asp----------------------------

<%
'Adjust this depending on the size of the files you'll
'be expecting; longer timeout for larger files!
Server.ScriptTimeout = 5400

Const ForWriting = 2
Const TristateTrue = -1
CrLf = Chr(13) & Chr(10)

'This function retreives a field's name
Function GetFieldName(infoStr)
    sPos = InStr(infoStr, "name=")
    EndPos = InStr(sPos + 6, infoStr, Chr(34) & ";")
    If EndPos = 0 Then
        EndPos = inStr(sPos + 6, infoStr, Chr(34))
    End If
    GetFieldName = Mid(infoStr, sPos + 6, endPos - _
        (sPos + 6))
End Function

'This function retreives a file field's filename
Function GetFileName(infoStr)
    sPos = InStr(infoStr, "filename=")
    EndPos = InStr(infoStr, Chr(34) & CrLf)
    GetFileName = Mid(infoStr, sPos + 10, EndPos - _
        (sPos + 10))
End Function

'This function retreives a file field's MIME type
Function GetFileType(infoStr)
    sPos = InStr(infoStr, "Content-Type: ")
    GetFileType = Mid(infoStr, sPos + 14)
End Function

'Yank the file (and anything else) that was posted
PostData = ""
Dim biData
biData = Request.BinaryRead(Request.TotalBytes)
'Careful! It's binary! So, let's change it into
'something a bit more manageable.
For nIndex = 1 to LenB(biData)
    PostData = PostData & Chr(AscB(MidB(biData,nIndex,1)))
Next

'Having used BinaryRead, the Request.Form collection is
'no longer available to us. So, we have to parse the
'request variables ourselves!
'First, let's find that encoding type!
ContentType = Request.ServerVariables( _
    "HTTP_CONTENT_TYPE")
ctArray = Split(ContentType, ";")
'File posts only work well when the encoding is
'"multipart/form-data", so let's check for that!
If Trim(ctArray(0)) = "multipart/form-data" Then
    ErrMsg = ""
    ' grab the form boundary...
    bArray = Split(Trim(ctArray(1)), "=")
    Boundary = Trim(bArray(1))
    'Now use that to split up all the variables!
    FormData = Split(PostData, Boundary)
    'Extract the information for each variable and its data
    Dim myRequest, myRequestFiles(9, 3)
    Set myRequest = CreateObject("Scripting.Dictionary")
    FileCount = 0
    For x = 0 to UBound(FormData)
        'Two CrLfs mark the end of the information about
        'this field; everything after that is the value
        InfoEnd = InStr(FormData(x), CrLf & CrLf)
        If InfoEnd > 0 Then
             'Get info for this field, minus stuff at the end
             varInfo = Mid(FormData(x), 3, InfoEnd - 3)
             'Get value for this field, being sure to skip
             'CrLf pairs at the start and the CrLf at the end
             varValue = Mid(FormData(x), InfoEnd + 4, _
                 Len(FormData(x)) - InfoEnd - 7)
             'Is this a file?
             If (InStr(varInfo, "filename=") > 0) Then
                 'Place it into our files array
                 '(While this supports more than one file
                 'uploaded at a time we only consider the
                 'single file case in this example)
                 myRequestFiles(FileCount , 0) = GetFieldName( _
                      varInfo)
                 myRequestFiles(FileCount , 1) = varValue
                 myRequestFiles(FileCount , 2) = GetFileName( _
                      varInfo)
                 myRequestFiles(FileCount , 3) = GetFileType( _
                      varInfo)
                 FileCount = FileCount + 1
             Else
                 'It's a regular field
                 myRequest.add GetFieldName(varInfo), varValue
             End If
        End If
    Next
Else
    ErrMsg = "Wrong encoding type!"
End If

'Save the actual posted file
'If supporting more than one file, turn this into a loop!

Dim strFilePath, strdisplayFilename

Set lf = server.createObject("Scripting.FileSystemObject")
If myRequest("filename") = "original" Then
    'Use the filename that came with the file
    'At this point, you need to determine what sort of
    'client sent the file. Macintoshes only send the file
    'name, with no path informat